Answer:
x = 9 is an extraneous solution.
Step-by-step explanation:
First of all, we need to figure out which of the values of x cannot be a solution to the equation.
When dealing with the real numbers, we need to take the square root of positive numbers only, which means we need [tex]x-5\geq 0\\\\x\geq 5[/tex].
While negative numbers can not give a solution with square roots so we can check with 9 to see if it is a true solution:
[tex]\sqrt{9-5} -\sqrt{9} =5\\\\2-3\neq 5[/tex]
Therefore, x = 9 is an extraneous solution.
