The distance of line AB if A(3, 5) and B(-3,-3) is D.10.
[tex]\sqrt[/tex] (5--3)^2 + (3-(-3))^2 = V100 = 10.
How to calculate the AB distance?
To calculate the distance AB between points A (x1, y1) and B (x2, y2), first draw a right triangle with segment ¯AB in the hypothalamus. AC is a horizontal distance, so it's just a difference in x-coordinates: | (x2-x1) |. Similarly, BC is the vertical distance | (y2-y1) |. ..
The vertical distance of the line (Ax + By + c = 0) from point
is equal to | Ax'+ By' + c√A2 + B2 |. Where (x', y') are the coordinates of the point. Since we need the distance of the line from the origin, the coordinates will be (0,0), which is the vertical distance of the line from the origin.
Learn more about distance in mathematics here: https://brainly.com/question/7243416
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