Respuesta :
Answer:
+ 7.
Explanation:
We have general rules to assign the oxidation numbers:
Rule 1: The oxidation number of an element alone in its free (uncombined) state is zero.
For example, Al(s) or Zn(s).
This is also true for elements found in nature as diatomic (two-atom) elements as: H₂, O₂, Cl₂, or I₂.
and also for sulfur, found as: S₈.
Rule 2: The oxidation number of a monatomic (one-atom) ion is the same as the charge on the ion,
For example: Na⁺ = +1, S⁻² = -2.
Rule 3: The sum of all oxidation numbers in a neutral compound is zero. The sum of all oxidation numbers in a polyatomic (many-atom) ion is equal to the charge on the ion.
Rule 4: The oxidation number of an alkali metal (group IA) in a compound is +1; the oxidation number of an alkaline earth metal (group IIA) in a compound is +2.
Rule 5: The oxidation number of oxygen in a compound is usually –2.
If, however, the oxygen is in a class of compounds called peroxides.
(for example, hydrogen peroxide), then the oxygen has an oxidation number of –1. If the oxygen is bonded to fluorine, the number is +1.
So, for our problem Ca(MnO₄)₂:
- The sum of all oxidation numbers in a neutral compound is zero.
- The oxidation no. of Ca which is in (group IIA) = +2.
- The oxidation no. of O = -2.
∴ oxidation no. of Ca + 2[(oxidation no. of Mn) + 4(oxidation no. of O) = 0.
(+2) + 2[(oxidation no. of Mn) + (- 8)] = 0.
2[(oxidation no. of Mn) + (- 8)] = - 2.
[(oxidation no. of Mn) + (- 8)] = -1.
∴ (oxidation no. of Mn) = - 1 + 8 = + 7.
+7 is the oxidation number of manganese atom (Mn) in Ca(MnO₄)₂.
What does oxidation number tells about?
Oxidation number of any substance will tell about the import and export number of electrons from that substance.
Given compound is Ca(MnO₄)₂, this is a neutral compound means no charge is present on the compound. Oxidation number of Calcium (Ca) is +2, oxidation number of oxygen atom (O) is -2 and let the oxidation number of manganese (Mn) be x.
Total sum of the oxidation number of all atoms equals to the whole charge of the compound and calculation for oxidation number will be calculated as:
+2 + 2[x + 4(-2)] = 0
2 + 2x - 16 = 0
2x = 16 - 2
2x = 14
x = 7
Hence, +7 is the oxidation number.
To know more about oxidation number, visit the below link:
https://brainly.com/question/8990767
