Respuesta :

SonOfZeus

Using the kinematic equation below we can determine the distance traveled if t=2, a=7.4m/s^2.  First we must determine the final velocity:

[tex]v_{final}=v_{initial}+\frac{1}{2}at\\\\v_{final}=0+(7.4m/s^2)(2s)=34.8m/s[/tex]

Now we will determine the distance traveled:

[tex]v_{final}^2=v_{initial}^2+2a \Delta x\\\\\Delta x = \frac{v_{final}^2}{2a} =\frac{(34.8)^2}{(2)(7.4)}=81.83 m[/tex]

Therefore, the drag racer traveled 81.83 meters in 2 seconds.

okpalawalter8

We have that When A drag racer starts from rest and accelerates at 7.4 m/s the distance travelled in 2.0 seconds is

S=14.8m

From the question we are told

A drag racer starts from rest and accelerates at 7.4 m/s2. How far will he travel in 2.0 seconds?

Generally the equation for the Distance  is mathematically given as

[tex]s=ut+1/2at^2\\\\Where\\\\Accelerates at 7.4 m/s2\\\\U=0\\\\T=2.0\\\\[/tex]

Hence

S=0+1/2(7.4)(2)^2

S=14.8m

Therefore

When A drag racer starts from rest and accelerates at 7.4 m/s the distance travelled in 2.0 seconds is

S=14.8m

For more information on this

https://brainly.com/question/23379286

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