a. The horizontal component of the truck's velocity is 5.69 m/s.
b. The vertical component of the truck's velocity is 21.25 m/s.
Given the following data:
- Angle of inclination = 15°
- Velocity of truck= 22 m/s
To find both the horizontal and vertical components of the truck's velocity:
a. To find the horizontal component of the truck's velocity:
Mathematically, the horizontal component of velocity is given by the formula:
[tex]V_y = Vsin(\theta)\\\\V_y = 22sin(15)\\\\V_y = 22 \times 0.2588[/tex]
Horizontal component, Vy = 5.69 m/s
b. To find the vertical component of the truck's velocity:
Mathematically, the vertical component of velocity is given by the formula:
[tex]V_x = Vcos(\theta)\\\\V_x = 22sin(15)\\\\V_x = 22 \times 0.9659[/tex]
Vertical component, Vx = 21.25 m/s
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