Respuesta :
Answer:
The girl threw the marshmallow with a speed of 35.4 m/s.
Explanation:
Use the formula for the range of projectile motion:
[tex]R = \frac{v^2\cdot \sin2\theta}{g}[/tex]
with R the range or distance (92m), theta the elevation angle (67 degrees) and g the gravitational acceleration. The velocity can be determined from this as follows:
[tex]|v| = \sqrt{\frac{R\cdot g}{\sin 2 \theta}} = \sqrt{\frac{92m\cdot 9.8 \frac{m}{s^2}}{\sin 134^\circ}}=35.40\frac{m}{s}[/tex]
The girl threw the marshmallow with a speed of 35.4 m/s, which is approximately 79 mph. No word on the boy's condition after the marshmallow's landing.