The answer is 0.000824653J
You need to use the formula Mass * Velocity^2 over 2
Answer:
The kinetic energy of the bullet is approximately 10688 Joules, or about 10.7kJ.
Explanation:
Use the kinetic energy formula:
[tex]E_k=\frac{1}{2}mv^2= \frac{1}{2}9.5\cdot10^{-3}kg\cdot 1.5^2\cdot 10^6 \frac{m^2}{s^2}\approx 10688J[/tex]
The kinetic energy of the bullet is approximately 10688 Joules, or about 10.7kJ.
