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a first class letter in 2013 costs $.46 for the first once and $0.20 for every additional once. ,The cost is c=.046 +.20(z-1), where z is the letter in ounces, solve for z.

Respuesta :

The cost is c=.46 +.20(z-1)

Solve for z

To solve for z, first we remove the parenthesis

c= .46 + .20z - .20

combine like terms

c= 0.26 + 0.20z

Now we need to get z alone

Subtract 0.26 on both sides

c - 0.26 = 0.20z

Now divide both sides by 0.20

[tex]\frac{c-0.26}{0.20}=z[/tex]

We got z alone

[tex]z=\frac{c-0.26}{0.20}[/tex]



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