The symbols for three different cations with 14 protons are Si²⁺, Si⁴⁺, and Si³⁺.
An element with 14 protons must be silicon, Si.
Its electron configuration is [Ne] 3s²3p², so it could lose up to four valence electrons.
The most likely cations are Si²⁺, Si⁴⁺, and Si³⁺ (or Si⁺).
Answer:
The cations are [tex]Si^+,Si^{2+},Si^{3+}[/tex]
Explanation:
Atomic number = Number of protons present in the nucleus of an atom of the element
Number of protons =14
Atomic number of an element will be 14.
The name of the element with 14 atomic number is silicon. It has equal number of electrons. Since an atom is a neutral species.
After loosing electrons atom gain positive charge.
[tex][Si]=1s^22s^22p^63s^23p^2[/tex]
After losing an electron is becomes [tex]Si^{+}[/tex]
[tex][Si^+]=1s^22s^22p^63s^23p^1[/tex]
After losing 2 electron is becomes [tex]Si^{2+}[/tex]
[tex][Si^{2+}]=1s^22s^22p^63s^23p^0[/tex]
After losing 3 electron is becomes [tex]Si^{3+}[/tex]
[tex][Si^{3+}]=1s^22s^22p^6[/tex]
