Let the number be 'x'
According to the question,
A number is added to 15 less than 3 times itself.
So, x + (15 less than 3 times itself)
15 less than 3 times itself = [tex]3x - 15[/tex]
Now, x + (15 less than 3 times itself) = [tex]x + (3x-15)[/tex]
We get the result as 101.
So, [tex]x+ 3x-15 = 101[/tex]
[tex]4x - 15 = 101[/tex]
Therefore, it is the required equation used to evaluate the number 'x'.
