Which description is true of 0.02 M Ca(OH)2 if Ca(OH)2 completely dissociates in water? A. It’s a dilute strong acid. B. It’s a dilute strong base. C. It’s a dilute weak base. D. It’s a concentrated weak base. E. It’s a concentrated weak acid.

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14-09-2018
Chemistry

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Which description is true of 0.02 M Ca(OH)2 if Ca(OH)2 completely dissociates in water? A. It’s a dilute strong acid. B. It’s a dilute strong base. C. It’s a dilute weak base. D. It’s a concentrated weak base. E. It’s a concentrated weak acid.

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tallinn tallinn · Answer 1 · 2018-09-14T19:01:51+02:00

Answer:- B. It's a dilute strong base.

Explanations:- The given concentration of calcium hydroxide is 0.02 M which is low means it is diluted. It has hydroxide ions which means it's a base. If it dissociates completely then it's a strong base. The dissociation equation is written as:

[tex]Ca(OH)_2(aq)\rightarrow Ca^+^2(aq)+2OH^-(aq)[/tex]

So, the correct option is B) It's a dilute strong base.