Answer:
x= 1 , x= -3/2
Step-by-step explanation:
[tex]2x^2 +x-1=2[/tex]
To solve for x we need to get 0 on the right side
Subtract 2 from both sides
[tex]2x^2 +x-3=0[/tex]
Now apply quadratic formula
[tex]x=\frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]
The value of a= 2, b= 1 and c= -3
Plug in the values in the formula
[tex]x=\frac{-1+-\sqrt{1^2-4(2)(-3)}}{2(2)}[/tex]
[tex]x=\frac{-1+-\sqrt{25}}{2(2)}[/tex]
[tex]x=\frac{-1+-5}{4}[/tex]
[tex]x=\frac{-1+5}{4}=1[/tex]
[tex]x=\frac{-1-5}{4}=\frac{-3}{2}[/tex]
