Respuesta :
Now despite what you may believe, 1:3 is not 1/3 in this situation. In this case, it means "1 equal part to 3 equal parts", which is a total of 4 equal parts. In short, this question is to place point P 1/4 the distance from A to B.
Firstly, how far apart is -1 from 7 (the x-coordinates)? That would be 8 units. Multiply 1/4 by 8:
[tex]\frac{1}{4}\times \frac{8}{1}=\frac{8}{4}=2[/tex]
Next, how far apart is 2 from 8 (the y-coordinates)? That would be 6 units. Multiply 1/4 by 6:
[tex]\frac{1}{4}\times \frac{6}{1}=\frac{6}{4}=\frac{3}{2}[/tex]
Next, since from -1 to 7 you are increasing, add 2 to -1:
[tex]-1+2=1[/tex]
1 is your x-coordinate
Next, since from 2 to 8 you are increasing, add 3/2 to 2:
[tex]\frac{2}{1}\times \frac{2}{2}=\frac{4}{2}\\\\\frac{4}{2}+\frac{3}{2}=\frac{7}{2}[/tex]
7/2 is your y-coordinate.
Putting it together, your answer is A. (1, 7/2)
We need to find the coordinate that divides the line AB in the ratio 1:3.
The point P lies in A. [tex]\left(1,\dfrac{7}{2}\right)[/tex].
The points of the line are
[tex]A(-1,2)[/tex] and [tex]B(7,8)[/tex]
The ratio of division is [tex]m:n=1:3[/tex]
The formula for partitioning is
[tex]P=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)\\\Rightarrow P=\left(\dfrac{1\times 7+3\times-1}{1+3},\dfrac{1\times 8+3\times 2}{1+3}\right)\\\Rightarrow P=\left(\dfrac{7-3}{4},\dfrac{8+6}{4}\right)\\\Rightarrow P=\left(1,\dfrac{7}{2}\right)[/tex]
So, the point P lies in A. [tex]\left(1,\dfrac{7}{2}\right)[/tex].
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