Respuesta :

2*3=6

2*i =2i

3*-5i=-15i

and -5i*i=-5i^2 i^2=-1 so you actually have 5

5-15i+2i+6 simplifies to 11-13i

The standard form of the product of the complex numbers (2−5i)(3+i)  is 21 - 13i

Given the product of the complex numbers;

(2−5i)(3+i)

Expanding using distributive law;

[tex]= (2-5i)(3+i) \\= 2(3)+2i-15i-5i^2\\=6-13i-5i^2[/tex]

In complex number, note that i^2 = -1. Substituting this into the result will give;

[tex]=6-13i-15(-1)\\=6-13i+15\\= -13i+21\\= 21-13i[/tex]

Hence the standard form of the product of the complex numbers (2−5i)(3+i)  is 21 - 13i

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