we are given
[tex]\frac{x^3+10x^2+13x+39}{x^2+2x+1}[/tex]
we can use long division method
we get
[tex]b(x)=x^2+2x+1[/tex]
[tex]q(x)=x+8[/tex]
[tex]r(x)=-4x+31[/tex]
so, we can write our expression as
[tex]\frac{x^3+10x^2+13x+39}{x^2+2x+1}=(x+8) +\frac{-4x+31}{x^2+2x+1} [/tex]...........Answer
