Respuesta :
a. T = 87 F0
Temperature can be converted to celcius as follows:
F = (9 /5) C + 32
87 = (9 /5) C + 32
C = 30.55 C0
b. T = 25 C0
Temperature can be converted to kelvin as follows:
K = C + 273.15
= 30.55 + 273.15 = 303.7 K
F = (9 /5) C + 32
F = (9 /5) (25) + 32 = 77 F
c. T = 400 F
400 = (9 /5) C + 32
C = 204.44 C0
K = C + 273.15
K = 204.44 + 273.15 = 477.59 K
d . T = 77 K
77 K = C + 273.15
C = - 196.15 C0
F = (9 /5) C + 32
F = (9 /5) (- 196.15) + 32 = -321.07 F
Answer :
(a) The temperature in degree Celsius is, [tex]30.5^oC[/tex]
(b) The temperature in Kelvin and in degree Fahrenheit is, 298K and [tex]77^oF[/tex] respectively.
(c) The temperature in degree Celsius and Kelvin is, [tex]204.4^oC[/tex] and 477.4 K respectively.
(d) The temperature in degree Fahrenheit and Celsius is, [tex]-320.8^oF[/tex] and [tex]-196^oC[/tex] respectively.
Explanation :
The conversion used for the temperature from Fahrenheit to degree Celsius is:
[tex]^oC=(^oF-32)\times \frac{5}{9}[/tex]
where,
[tex]^oF[/tex] = temperature in Fahrenheit
[tex]^oC[/tex] = temperature in centigrade
The conversion used for the temperature from degree Celsius to Kelvin is:
[tex]K=273+^oC[/tex]
where,
[tex]K[/tex] = temperature in Kelvin
[tex]^oC[/tex] = temperature in centigrade
(a) As we are given the temperature in Fahrenheit is, [tex]87^oF[/tex]
Now we have to determine the temperature in degree Celsius.
[tex]^oC=(^oF-32)\times \frac{5}{9}[/tex]
[tex]^oC=(87^oF-32)\times \frac{5}{9}[/tex]
[tex]^oC=30.5[/tex]
(b) As we are given the temperature in degree Celsius is, [tex]25^oC[/tex]
Now we have to determine the temperature in Kelvin.
[tex]K=273+^oC[/tex]
[tex]K=273+25[/tex]
[tex]K=298[/tex]
Now we have to determine the temperature in degree Fahrenheit.
[tex]^oC=(^oF-32)\times \frac{5}{9}[/tex]
[tex]25^oC=(^oF-32)\times \frac{5}{9}[/tex]
[tex]^oF=77[/tex]
(c) As we are given the temperature in Fahrenheit is, [tex]400^oF[/tex]
Now we have to determine the temperature in degree Celsius.
[tex]^oC=(^oF-32)\times \frac{5}{9}[/tex]
[tex]^oC=(400^oF-32)\times \frac{5}{9}[/tex]
[tex]^oC=204.4[/tex]
Now we have to determine the temperature in Kelvin.
[tex]K=273+^oC[/tex]
[tex]K=273+204.4[/tex]
[tex]K=477.4[/tex]
(d) As we are given the temperature in Kelvin, 77 K
Now we have to determine the temperature in degree Celsius.
[tex]K=273+^oC[/tex]
[tex]77=273+^oC[/tex]
[tex]^oC=-196[/tex]
Now we have to determine the temperature in degree Fahrenheit.
[tex]^oC=(^oF-32)\times \frac{5}{9}[/tex]
[tex]-196^oC=(^oF-32)\times \frac{5}{9}[/tex]
[tex]^oF=-320.8[/tex]
