So for eyes' sake, I will be using different brackets to read the equation better. Here's how to solve this expression:
[tex] (\{[4^2-(7*2)]^4*2\}-2)\div 3+(5*2)\div 2-5\\ (\{[16-14]^4*2\}-2)\div 3+10\div 2-5\\ (\{2^4*2\}-2)\div 3+5-5\\ (\{16*2\}-2)\div 3+5-5\\ (32-2)\div 3+5-5\\ 30\div 3+5-5\\ 10+5-5\\ 10 [/tex]
The answer is 10.
