An emf source of 6.0V is connected to a purely resistive lamp and a current of 2.0 amperes flows. All the wires are resistance-free. What is the resistance of the lamp?

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13-06-2018
Physics

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An emf source of 6.0V is connected to a purely resistive lamp and a current of 2.0 amperes flows. All the wires are resistance-free. What is the resistance of the lamp?

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AL2006 AL2006 · Answer 1 · 2018-06-14T00:19:41+02:00

AL2006 AL2006

14-06-2018

Resistance = (voltage) / (current)

Resistance = (6.0 v) / (2.0 A)

Resistance = 3.0 ohms

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okpalawalter8 okpalawalter8 · Answer 2 · 2021-10-15T12:32:10+02:00

We have that With the wires are resistance-free the resistance of the lamp is

[tex]R=3 \omega[/tex]

From the question we are told

An emf source of 6.0V is connected to a purely resistivity lamp and a current of 2.0 amperes flows. All the wires are resistance-free. What is the resistance of the lamp?

Generally the equation for the EMF is mathematically given as

V=IR

Therefore

I=2A

R=E/I

And

R=6/2

[tex]R=3 \omega[/tex]

Therefore

With the wires are resistance-free the resistance of the lamp is

[tex]R=3 \omega[/tex]

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