Respuesta :

[tex]\begin{cases}a(0)=1\\a(n+1)=2a(n)+2&\text{for }n\ge0\end{cases}[/tex]

Use the second part of the definition (the recursive one):


[tex]a(1)=2a(0)+2=4[/tex]
[tex]a(2)=2a(1)+2=10[/tex]
[tex]a(3)=2a(2)+2=22[/tex]