the correct question is
The area of the larger circle is 36pi in(squared). Find the circumference of one of the smaller circles.
A=3pi in.
B=6pi in.
C=9pi in.
D=18pi in
the picture in the attached figure
we know that
area of a circle=pi*r²
area of the larger circle=36*pi in²
36*pi=pi*r²
r²=36
r=√36-------> r=6 in
the diameter of one of the smaller circles is equal to the radius of the larger circle
so
diameter smaller circle=6 in
circumference=pi*D
where D is the diameter
so
the circumference of one of the smaller circle=6*pi in
the answer is
6*pi in
