contestada

What is the initial temperature of a gas if the volume changed from 1.00 l to 1.10 l and the final temperature was determined to be 255.0°c? 232°c -41°c 207°c 480°c none of the above?

Respuesta :

olabido
using charles law
v1/t1=v2/t2
v1=1l
v2=1.1l
t2=255+273=528
t1=?
1/t1=1.1/528   
cross multiply
1.1t1=528 divide both sides by 1.1
t1=528/1.1
t1=480k or 207celcius

Answer : The initial temperature of gas is [tex]207^oC[/tex]

Explanation :

Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

[tex]V\propto T[/tex]

or,

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where,

[tex]V_1[/tex] = initial volume of gas = 1.00 L

[tex]V_2[/tex] = final volume of gas = 1.10 L

[tex]T_1[/tex] = initial temperature of gas = ?

[tex]T_2[/tex] = final temperature of gas = [tex]255.0^oC=273+255.0=528.0K[/tex]

Now put all the given values in the above equation, we get:

[tex]\frac{1.00L}{T_1}=\frac{1.10L}{528.0K}[/tex]

[tex]T_1=480K=480-273=207^oC[/tex]

Therefore, the initial temperature of gas is [tex]207^oC[/tex]