∴ 8x² + 5 = 35
∴ combining like terms by moving the constant to the right side
8x² = 35 - 5
8x² = 30
∴ divide both side by 2
4x² = 15
∴ solve for x²
x² = [tex] \dfrac{15}{4} [/tex]
∴ solve for x
solution 1
x = [tex] \sqrt{ \dfrac{15}{4} } [/tex]
x = [tex] \dfrac{1}{2} \sqrt{15} [/tex]
x = [tex]\dfrac{1}{2} \times 3.87298[/tex]
x = 1.936
to the nearest hundredth
x = 1.94
solution 2
x = [tex] -\sqrt{ \dfrac{15}{4} } [/tex]
x = [tex] -\dfrac{1}{2} \sqrt{15} [/tex]
x = [tex]- \dfrac{1}{2} \times 3.87298[/tex]
x = -1.936
to the nearest hundredth
x = -1.94
The answer is approximately 1.94 or -1.94
