Just how? (2a^2 c^4) ^-5 (c^-1 a^7)^6
ANSWER.
[tex]\boldsymbol {(2^2 \ c^4)^{-5} (c^{-1} \ a^7)^6}\\
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\boldsymbol {= 2^{-10} \ c^{-20} \ (c^{-1} \ a^7)^6}\\
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\boldsymbol {= 2^{-10} \ c^{-20} \ c^{-6} \ a^{42}}\\
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\boldsymbol {= 2^{-10} \ a^{42} \ c^{-26}}\\
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\boldsymbol {\dfrac{1}{2^{10}} \ a^{42} \ c^{-26}}\\
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\boldsymbol {\dfrac{1}{2^{10}} \ a^{42} \ \dfrac{1}{c^{26}}}\\
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\boldsymbol {\dfrac{1 \ \cdot \ 1 \ \cdot a^{42}}{2^{10} \ c^{26}}}\\
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\boldsymbol {= \dfrac{a^{42}}{1024c^{26}} \ \checkmark.}[/tex]
[tex]\boldsymbol {\dfrac{a^{42}}{1024c^{26}} \Leftarrow \underline{Answer}}[/tex]
REGARDS!