Respuesta :

check the picture below.

[tex]\bf \stackrel{(x+4)+1}{(x+5)}(x+4)=\stackrel{(x+1)+11}{(x+12)}(x+1)\implies x^2+9x+20=x^2+13x+12 \\\\\\ 9x+20=13x+12\implies 8=4x\implies \cfrac{8}{4}=x\implies 2=x[/tex]
Ver imagen jdoe0001