Answer : The specific heat of the substance is 0.0936 J/g °C
Explanation :
The amount of heat Q can be calculated using following formula.
[tex] Q = m \times C \times \bigtriangleup T [/tex]
Where Q is the amount of heat required = 300 J
m is the mass of the substance = 267 g
ΔT is the change in temperature = 12°C
C is the specific heat of the substance.
We want to solve for C, so the equation for Q is modified as follows.
[tex] C = \frac{Q}{m \times \bigtriangleup T} [/tex]
Let us plug in the values in above equation.
[tex] C = \frac{300J}{267g \times 12 C} [/tex]
[tex] C = \frac{300J}{3204 g C} [/tex]
C = 0.0936 J/g °C
The specific heat of the substance is 0.0936 J/g°C
