Tamara invests $8000 in two different accounts. The first account has a simple interest rate of 3% and the second account has a simple interest rate of 2%. How much did she invest in each account if the interest earned in them is the same at the end of one year?

Respuesta :

Let Tamara invests amount [tex] X [/tex] in 3% account. She invests [tex] 8000-X [/tex] in 2% account.

The interest after t years is given by

[tex] I=Prt [/tex]. After 1 year the two interests are equal, that is

[tex] X(\frac{3}{100}) (1)=(8000-X)(\frac{2}{100}) (1)\\
3X=2(8000-X)\\
5X=16000\\
X=3200 [/tex]

Thus, Tamara has to invest [tex] \$3200 [/tex] in 3% account and [tex] \$8000-\$3200=\$4800 [/tex] in 2% account.