contestada

Upon balancing the equation below, how many moles of calcium chloride are needed to react completely with 4.3 moles of silver nitrate? agno3 + cacl2 yields agcl + ca(no3)2 1.4 mol cacl2 2.2 mol cacl2 4.3 mol cacl2 8.6 mol cacl2

Respuesta :

Dangerous321
2.2 mol CaCl2 is the answer. 

Answer: The correct answer is 2.2 moles of [tex]CaCl_2[/tex]

Explanation:

For the given balanced equation:

[tex]2AgNO_3+CaCl_2\rightarrow 2AgCl+Ca(NO_3)_2[/tex]

By Stoichiometry of the reaction:

2 moles of silver nitrate reacts with 1 mole of calcium chloride.

So, 4.3 moles of silver nitrate will react with = [tex]\frac{1}{2}\times 4.3=2.15moles\approx 2.2moles[/tex] of calcium chloride.

Hence, the correct answer is 2.2 moles of [tex]CaCl_2[/tex]

Otras preguntas