Attached is the MOT of NO molecule.
1. Bond order is calculated is [tex] \frac{\text{number of e- in bonding orbital - number of e- in antibonding molecular orbital }}{2} [/tex]
In present case, number of e- in bonding orbital = 6
number of e- in anti-bonding orbital = 1
∴ Bond-order = [tex] \frac{\text{6-1 }}{2} [/tex] = 2.5
2. From the attached figure, it can be seen that NO has one unpaired electron in π* orbital.
