Respuesta :

calculista
we know that
The quotient of
-8x²y³/xy=-8xy²

then 
the product of
(4xy)*z= -8xy²------> z=-8xy²/(4xy)-----> z=-2y

the answer is
-2y
so
The quotient of -8x²y³/xy is same as the product of (4xy)*(-2y) 

Answer:

The quotient of -8x^2y^3/xy is same as the product of 4xy and -2y.

Step-by-step explanation:

First find the quotient:

[tex]\frac{-8x^{2} y^{3} }{xy} \\=-8x^{2} y^{3} *x^{-1} y^{-1} \\=-8xy^{2}[/tex]

The quotient should be equal to 4xy times an unknown quantity. Set the unknown quantity equal to a:

[tex]4xy*a=-8xy^{2} \\a=\frac{-8xy^{2}}{4xy} \\a=-2xy^{2}*x^{-1} y^{-1} \\a=-2y[/tex]

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