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jbsalonga08
Answer is 15 combinations of 2 people from 6 will be able to sit on front row.

The formula used is Formula for Combinations.
Where N = Objects equal to 6 people
and r = Sample or 2 Samples
We are to form the combination of 6 objects taken 2 at a time. This can be expressed as 6C2

[tex]6C2= \frac{6!}{2!*4!} \\ \\ = \frac{6*5}{2} \\ \\ =15 [/tex]

This means, there can be 15 different combinations of 2 members that can sit in the front row.

So, the answer to this question is option A

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