Answer:
1.41 g of H₂O
Solution:
The equation for given reaction is as follow,
Cu₂O + H₂ → 2 Cu + H₂O
According to equation,
127 g (2 mole) Cu is produced along with = 18 g (1 mole) of H₂O
So,
10 g Cu produced will generate = X g of H₂O
Solving for X,
X = (18 g × 10 g) ÷ 127 g
X = 1.41 g of H₂O