Alex laughed a ball into air the height of the ball can be represented by the equation h=-8t +40t+5, where h is the height in units,and t is the time ,in seconds,after the ball was launched. Graph the equation frim t=0 to t=5 seconds.
For this case the correct equation should be: h = -8t ^ 2 + 40t + 5 We observe that we have a parabola. The direction of the parabola is opening downwards. This is because the coefficient of the quadratic term is negative. We must graph the function in the following domain: [0, 5] Answer: see attached image
