Respuesta :
Let the number of each coin be n.
The total sum of these coins is $4.40. So we can write:
n Nickles + n Dimes + n Quarters = 4.40
0.05n + 0.10n + 0.25n = 4.40
0.40n = 4.40
n = 11
So this means, there are 11 coins of each type.
The total sum of these coins is $4.40. So we can write:
n Nickles + n Dimes + n Quarters = 4.40
0.05n + 0.10n + 0.25n = 4.40
0.40n = 4.40
n = 11
So this means, there are 11 coins of each type.