According to a recent study, 12% of peanut M&M's are brown, 3% are yellow, 21% are red, 28% are blue, 28% are orange, and 9% are green. Assume these proportions are correct and suppose you randomly select six peanut M&M's from an extra-large bag of the candies. Calculate the following probablities. Also calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places, if necessary.
Compute the probability that exactly three of the six M&M's are blue.
P(r = 3) =