Given that this reaction below has an equilibrium constant of Kp = 2.2 x 106 at 298 K

2COF2 (g) ↔ CO2 (g) + CF4 (g)

What would be the Kp value for the reaction below be.

2CO2 (g) + 2CF4 (g) ↔ 4COF2 (g) Kp = x10^

Give the answer to two sig figs for the first box. Also the number requires scientific notation so the two boxes are for the number and the power it needs to be raised to.

Answers: 2.1 x10^-13