What is the general solution to the differential equation y' = (3x^4 + y^4)/(xy³)?

A) y = -(1/2)Cx^4ln(x) + x^12y^4
B) y = 12Cx^4ln(x) + x^4y
C) y = 12x^4ln(x) + Cx^4y^4
D) y = -(1/2)x^4ln(x) + Cx^12