A survey found that out of 250 workers, 165 said they were interrupted three or more times an hour by phone messages, emails, etc.
(a) Find a point estimate p^ for the proportion of all workers who are interrupted three or more times an hour. (Round to 2 decimal places.)
(b) Find a 98% confidence interval of the population proportion of workers who are interrupted three or more times an hour.
We find a confidence interval for the population proportion using p^−E
To find E, we need the correct critical value and formula for the correct distribution.
critical value = (Round to 2 decimal places.)
E = (Round to 2 decimal places.)
98% Confidence Interval:
