Consider the half reactions one more time. Will the reaction as written here occur spontaneously?
Fe2+ (aq) +2 e-→ Fe(s) E° = -0.447 V
Cu2+ (aq) +2 e-→ Cu(s) E° = 0.342 V
Fe2+ (aq) + Cu(s) → Cu²+ (aq) + Fe(s)

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