meshiah12345 meshiah12345
  • 13-12-2022
  • Mathematics
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CB // ED and both of BD and CE are transversals
The point E will be the image of point C by rotation 180° around point F
And The point D will be the image of point B by rotation 180° around point F
Rotation is a kind of transformation
So, ΔEDF will be the image of ΔCBF
So, ΔCBF ≅ ΔEDF

CB ED and both of BD and CE are transversals The point E will be the image of point C by rotation 180 around point F And The point D will be the image of point class=

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