Find an equation of the tangent line to the given curve at the specified point. ex y = (1, e) х Step 1 To find the equation of a line with slope m through a point (xo, Yo), we can use y - yo = m(x – Xo). For y = f(x), the slope of the tangent line at (xo, Yo) is given by m = f'(xo). We have y = et. Therefore, we differentiate using the Quotient Rule. (x).( y' = et (1) et x2 Step 2 Thus, the tangent slope at the point (1, e) is as follows. (1) ).( e (el). (1) m = f '(1) = Suppose that f(2) = -5, 9(2) = 2, f '(2) = -4, and g'(2) = 1. Find h(2). (a) h(x) = 2f(x) – 49(x) h'(2) h(x) = f(x)g(x) (b) h'(2) (c) h(x) = f(x) g(x) h'(2) = (d) h(x) = g(x) 1 + f(x) h'(2) =